Question 1068040: Tickets numbered 1 to 10 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number, which is a multiple of 2 or 3? Please help me by showing work, indicating which formula for calculating probabilities were used.
Found 2 solutions by stanbon, addingup:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Tickets numbered 1 to 10 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number, which is a multiple of 2 or 3? Please help me by showing work, indicating which formula for calculating probabilities were used.
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Ans: P(mult of 2) + P(mult of 3) - P(mult of 2 and mult of 3)
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= [5 + 3 - 1]/10
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= 7/10
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Cheers,
Stan H.
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Answer by addingup(3677)  (Show Source):
You can put this solution on YOUR website! multiple of 3: 6, 9 total 2
multiple of 2: 4, 6, 8, 10 total 4
2+4 = 6
what's the probability of drawing
one of these 6 out of a possible 10?
6 ÷ 10 = 0.6 or 60%
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