SOLUTION: 6e+u=3 e^2+u^2=16

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Question 1067917: 6e+u=3
e^2+u^2=16
Answer by josgarithmetic(39615) About Me  (Show Source):
You can put this solution on YOUR website!
Substituting for u from the linear equation into the degree-two equation will give you 37e%5E2-36d-7=0. You can continue solving from this.

General solution of quadratic equation gives e=%2818%2B-+sqrt%28583%29%29%2F37. Use this to continue finding corresponding values for u.