SOLUTION: Problem Page Keisha drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 6 hours. When Keisha drove home, there was no traffic and

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Question 1067866: Problem Page
Keisha drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took
6
hours. When Keisha drove home, there was no traffic and the trip only took
4
hours. If her average rate was
22
miles per hour faster on the trip home, how far away does Keisha live from the mountains?
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39623) (Show Source):
You can put this solution on YOUR website!
Constant Travel Rates Rule, RT=D for RATE, TIME, DISTANCE

SPEED TIME DISTANCE GOING r 6 d RETURNING r+22 4 d

System of Equations

Same d both directions;

Solve for r, the speed GOING TO the mountains.

Answer by MathTherapy(10555) (Show Source):
You can put this solution on YOUR website!

Problem Page
Keisha drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took
6
hours. When Keisha drove home, there was no traffic and the trip only took
4
hours. If her average rate was
22
miles per hour faster on the trip home, how far away does Keisha live from the mountains?

Let the distance to the mountains be D
Then speed to the mountains =
Speed on return trip =
We then get the following SPEED equation:
Solve this to get a distance of:
That's all...nothing CONFUSING and/or COMPLEX!