SOLUTION: Katie has a collection of nickels, dimes and quarters with a total value of $6.10. There are 3 more dimes than nickels and 4 more quarters than nickels, how many of each coin does

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Question 1067798: Katie has a collection of nickels, dimes and quarters with a total value of $6.10. There are 3 more dimes than nickels and 4 more quarters than nickels, how many of each coin does she have?
Answer by ikleyn(52775) About Me  (Show Source):
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Katie has a collection of nickels, dimes and quarters with a total value of $6.10.
There are 3 more dimes than nickels and 4 more quarters than nickels, how many of each coin does she have?
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Let N be the number of nickels.
Then the number of dimes is (N+3) and the number of quarters is (N+4).

The nickels contribute 5N        cents to the total.
The dimes   contribute 10*(N+3) cents to the total.
The dimes   contribute 25*(N+4) cents to the total.

The "value" equation is

5N + 10(N+3) + 25(N+4) = 610 cents,   or

5N + 10N + 30 + 25N + 100 = 610,   or

40N = 610 - 30 - 100,

40N = 480,

N = 480%2F40 = 12.


Answer.  12 nickels,   12+3 = 15 dimes  and  12+4 = 16 quarters.

Solved.


There is entire bunch of lessons on coin problems
    - Coin problems
    - More Coin problems
    - Solving coin problems without using equations
    - Kevin and Randy Muise have a jar containing coins
    - Typical coin problems from the archive
    - More complicated coin problems
    - Solving coin problems mentally by grouping without using equations
    - Santa Claus helps solving coin problem
    - OVERVIEW of lessons on coin word problems
in this site.

Read them and become an expert in solution of coin problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Coin problems".