Question 1067594: John is twice as old as Jane was when he was as old as she is now. The sum of their age is 63. How old is John and Jane
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John is twice as old as Jane was when he was as old as she is now. The sum of their age is 63. How old is John and Jane
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Let x be the John's present age and y be the Jane's present age.
When John was as old as Jane is now ? - Answer: (x-y) years ago.
What was Jane's age then? - Answer: y - (x-y) years, or, which is the same, 2y - x was Jane's age then.
The condition says:
x = 2 *(2y-x), or
x= 4y - 2x, or
3x = 4y. (1)
The second equation is
x + y = 63. (2)
From (2), express x = 63-y and substitute it into (2), replacing x. You will get
3*(63-y) = 4y, or
189 - 3y = 4y ---> 189 = 7y ---> y = = 27.
Answer. Jane is 27 years old. John is = 36 years old.
Solved.
For similar solved problems see the lesson
- Really intricate age word problem
in this site.
There is a bunch of lessons on age word problems
- Age problems and their solutions
- A fresh formulation of a traditional age problem
- Really intricate age word problem (*)
- Selected age word problems from the archive
- Age problem for the day of April, 1
- OVERVIEW of lessons on age problems
in this site.
Read them and become an expert in solving age problems.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Age word problems".
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