Question 1067225: Two years ago, my age was four times that of my son. Eight years ago, my age was ten times that of my son. Find the age of my son now.
Found 4 solutions by stanbon, addingup, MathTherapy, ikleyn:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Two years ago, my age was four times that of my son. Eight years ago, my age was ten times that of my son. Find the age of my son now.
-----
Equations:
m-2 = 4(s-2)
m-8 = 10(s-8)
------------------------
Rearrange:
m = 4s - 6
m = 10s - 80
------------------
4s-6 = 10s-80
6s = 74
s = 12 1/3 years OR 12 yrs 4 mths
-----------------
Stan H.
--------------
Answer by addingup(3677)  (Show Source):
You can put this solution on YOUR website! f-4 = 4(s-4)
f-4 = 4s-16
f = 4s-12
4s-f = 12 (1)
<><><><><><><><><><><>
f-8 = 10(s-8)
f-8 = 10s-80
f = 10s-72
10s-f = 72 (2)
<><><><><><><><><><><><>
multiply all terms in (1) times -1 and add to (2):
10s-f = 72
+
-4s+f = -12
------------
6s+0 = 60
6s = 60
s = 10 the son is 10. And the father is:
f-4 = 4(10-4)
f-4 = 24
f = 28 the father is 28
Check: let's try the answers on the second equation
f-8 = 10(s-8)
28-8 = 10(10-8)
20 = 10(2) and 10*2 is 20, my answer is correct.
Answer by MathTherapy(10552)  (Show Source):
You can put this solution on YOUR website!
Two years ago, my age was four times that of my son. Eight years ago, my age was ten times that of my son. Find the age of my son now.
The son is: 
All other "answers" are INCORRECT/WRONG/INACCURATE, and RIDICULOUS!
Answer by ikleyn(52794)  (Show Source):
|
|
|
