SOLUTION: In triangle ABC , m<B = 60 degree. Prove that m( AC)^2=(mAB)^2+(mBC)^2-(mAB).(mCB)

Algebra ->  Triangles -> SOLUTION: In triangle ABC , m<B = 60 degree. Prove that m( AC)^2=(mAB)^2+(mBC)^2-(mAB).(mCB)       Log On