SOLUTION: A piece of a wire measuring 20ft is attached to a telephone pole as a guy wire. The distance along the ground from the bottom of the pole to the end of the wire is 4ft greater than

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Question 1067082: A piece of a wire measuring 20ft is attached to a telephone pole as a guy wire. The distance along the ground from the bottom of the pole to the end of the wire is 4ft greater than the height where the wire is attached to the pole. How far up the pole does the guy wire reach?
(x + 4)^2 + (x)^2 = (20)^2

Found 2 solutions by stanbon, MathTherapy:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A piece of a wire measuring 20ft is attached to a telephone pole as a guy wire. The distance along the ground from the bottom of the pole to the end of the wire is 4ft greater than the height where the wire is attached to the pole. How far up the pole does the guy wire reach?
(x + 4)^2 + (x)^2 = (20)^2
----
x^2+8x+16 + x^2 = 400
----
8x+16 = 400
x + 2 = 50
x = 48 ft
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Cheers,
Stan H.
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Answer by MathTherapy(10556) About Me  (Show Source):
You can put this solution on YOUR website!
A piece of a wire measuring 20ft is attached to a telephone pole as a guy wire. The distance along the ground from the bottom of the pole to the end of the wire is 4ft greater than the height where the wire is attached to the pole. How far up the pole does the guy wire reach?
(x + 4)^2 + (x)^2 = (20)^2
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FYI The height CAN NEVER be 48 feet, so pay no attention to the person who says so.
How can a leg form a triangle be longer than its hypotenuse?