SOLUTION: Prove that the ratio of the areas of 2 similar triangles is equal to the square of the ratio of thier corresponding sides.

Lets say triangle A is similar to triangle B…

A has sides  a,b,c, and height h
B has corresponding sides d,e,f, and height g

Area of A =  (1/2)(a)(h) 

Area of B = (1/2)(d)(g)

There is a scale factor s that relates a to d, b to e, c to f, and h to g

        a = s*d
        b = s*e
        c = s*f
        h = s*g

       So area of A can be re-written as