SOLUTION: The sum of the squares of two numbers is 117. The square of smaller number is four times of the bigger number

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Question 1066990: The sum of the squares of two numbers is 117. The square of smaller number is four times of the bigger number

Found 2 solutions by josgarithmetic, Alan3354:
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
system%28x%5E2%2By%5E2=117%2Cx%5E2=4y%29

x%5E2%2B%284y%29%5E2=117

17y%5E2=117

y=sqrt%28117%2F17%29 and %29



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"The square of smaller number is four times of the bigger number"
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Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The sum of the squares of two numbers is 117. The square of smaller number is four times of the bigger number
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x^2 + y^2 = 117
x^2 = 4y
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y^2 + 4y - 117 = 0
y = 9
x = 6