SOLUTION: The P(A)=8/15, P(B)=3/4 and P(A∩B)=1/6. a) Find P(A∪B) b)Are A and B exhaustive events?

Algebra ->  Finance -> SOLUTION: The P(A)=8/15, P(B)=3/4 and P(A∩B)=1/6. a) Find P(A∪B) b)Are A and B exhaustive events?       Log On


   



Question 1066922: The P(A)=8/15, P(B)=3/4 and P(A∩B)=1/6. a) Find P(A∪B)
b)Are A and B exhaustive events?

Answer by Edwin McCravy(20059) About Me  (Show Source):
You can put this solution on YOUR website!
P(A)=8/15, P(B)=3/4 and P(A∩B)=1/6. a) Find P(A∪B)
a) Find P(A∪B)
P(A∪B) = P(A) + P(B) - P(A∩B) = 8/15 + 3/4 - 1/6 = 67/60 > 1

The problem is botched, because it's impossible to have a
probability > 1.  Did you copy the problem wrong?

Edwin