SOLUTION: Can someone help me please? factor to find all the real zeros of 3x^3+7x^2-6x. Thank You.

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Can someone help me please? factor to find all the real zeros of 3x^3+7x^2-6x. Thank You.      Log On


   

Question 106680: Can someone help me please? factor to find all the real zeros of 3x^3+7x^2-6x. Thank You.
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Factor:
3x%5E3%2B7x%5E2-6x First, factor an x from each term.
x%283x%5E2%2B7x-6%29 now factor the trinomial inside the parentheses.
x%283x-2%29%28x%2B3%29 To find the zero, set this equal to 0 and apply the zero products principle.
x%283x-2%29%28x%2B3%29+=+0 x+=+0
3x-2+=+0 so 3x+=+2 and x+=+2%2F3
x%2B3+=+0 so x+=+-3
The zeros are:
x+=+0
x+=+2%2F3
x+=+-3