Question 1066660: Cathy and Ernie had four consecutive even integers. They found that the product of the second and fourth was 16 less than the product of -3 and the sum of the first and third. What were their integers?
I got X^2 +8x+12=-6x-28. Then:x^2 +14x+40=0. Next: (x+4)(x+10)=0. Finally: x=-4, x=-10
Found 2 solutions by ikleyn, Boreal:
Answer by ikleyn(52817)   (Show Source):
Answer by Boreal(15235)  (Show Source):
You can put this solution on YOUR website! x,x+2,x+4,and x+6
x^2+8x+12+16=-3(2x+4)
x^2+8x+28=-6x-12
x^2+14x+40=0
(x+10)(x+4)=0, as you got
-10,-8,-6,-4.
product of second and fourth is 32 and that is 16 fewer than -3(-16)=48
try
-4,-2,0,2
product of second and fourth is -4 and that is 16 fewer than -3(-4)=12
Two solutions you have above work.
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