SOLUTION: Divide 3x^3 - 2x^2 - 61x - 20 by x - 5. A.)3x^2 + 13x + 4 B.)3x^2 - 13x + 4 C.)3x^2 - 17x + 24 R 100 D.)3x^2 + 17x - 24 R 100

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Divide 3x^3 - 2x^2 - 61x - 20 by x - 5. A.)3x^2 + 13x + 4 B.)3x^2 - 13x + 4 C.)3x^2 - 17x + 24 R 100 D.)3x^2 + 17x - 24 R 100       Log On


   

Question 1066623: Divide 3x^3 - 2x^2 - 61x - 20 by x - 5.
A.)3x^2 + 13x + 4
B.)3x^2 - 13x + 4
C.)3x^2 - 17x + 24 R 100
D.)3x^2 + 17x - 24 R 100

Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
5/3===-2====-61===-20
===3==13====4=====0
this divides evenly to give (x-5)(3x^2+13x+4), and when you multiply those out, it is 3x^3+13x^2+4x-15x^2-65x-20.
A.