SOLUTION: Find the quotient of the complex numbers. Leave answer in polar form. z1 = sqrt(3)(cos 7pi/4 + i sin 7pi/4) z2 = sqrt(6)(cos 9pi/4 +i+sin 9pi/4) A. sqrt(2)/2 (cos 3p

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: Find the quotient of the complex numbers. Leave answer in polar form. z1 = sqrt(3)(cos 7pi/4 + i sin 7pi/4) z2 = sqrt(6)(cos 9pi/4 +i+sin 9pi/4) A. sqrt(2)/2 (cos 3p      Log On


   



Question 1066575: Find the quotient of the complex numbers. Leave answer in polar form.
z1 = sqrt(3)(cos 7pi/4 + i sin 7pi/4)
z2 = sqrt(6)(cos 9pi/4 +i+sin 9pi/4)
A. sqrt(2)/2 (cos 3pi/2 - i sin 3pi/2)

B. sqrt(2)/2(cos 3pi/2 - i sin 3pi/2

C. sqrt(2)/2(sin 3pi/2 +i cos 3pi/2)
D. sqrt(2)/2(cos 3pi/2 +i sin 3pi/2)

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find the quotient of the complex numbers. Leave answer in polar form.
z1 = sqrt(3)(cos 7pi/4 + i sin 7pi/4)
z2 = sqrt(6)(cos 9pi/4 +i+sin 9pi/4)
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quotient = z1/z2 = [sqrt(3)/sqrt(6)][cos(-pi/2+i*sin(-pi)]
= [sqrt(2)/2][cos(3pi/2) + i*sin(3/pi/2)]
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D. sqrt(2)/2(cos 3pi/2 +i sin 3pi/2)
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Cheers,
Stan H.