SOLUTION: I need help on finding the remaining zeros of this problem. Degree 4; zeros: i, 2, -2

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Question 1066498: I need help on finding the remaining zeros of this problem.
Degree 4; zeros: i, 2, -2
Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
.
My dear, 

for polynomials with real coefficients,

complex zeroes ALWAYS go in pairs (complex number, conjugate complex number).

Since you are given complex root i = sqrt%28-1%29, the conjugate number -i is ALSO the root.

Therefore, your answer is -i: "minus i".

On complex numbers see the lessons
    - Complex numbers and arithmetic operations on them
    - Complex plane
    - Addition and subtraction of complex numbers in complex plane
    - Multiplication and division of complex numbers in complex plane
in this site.