SOLUTION: If A and B are two events such that P(A) = 1/4, P(B) = 1/3 and P(AUB) = 1/2, then find P(A∩B)

Algebra ->  Probability-and-statistics -> SOLUTION: If A and B are two events such that P(A) = 1/4, P(B) = 1/3 and P(AUB) = 1/2, then find P(A∩B)      Log On


   



Question 1066488: If A and B are two events such that P(A) = 1/4, P(B) = 1/3 and P(AUB) = 1/2, then find P(A∩B)
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

P(A∩B) = P(A) + P(B) - P(A u B)
P(A∩B) = 1/4 + 1/3 - 1/2
P(A∩B) = 3/12 + 4/12 - 6/12
P(A∩B) = (3+4-6)/12
P(A∩B) = 1/12