SOLUTION: the width of a rectangle is 5cm lesd than its lenght and its perimeter is 46cm. find width and area
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Question 1066400
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the width of a rectangle is 5cm lesd than its lenght and its perimeter is 46cm. find width and area
Answer by
addingup(3677)
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W = L-5
2L+2W = 46 substitute for W:
2L+2(L-5) = 46
2L+2L-10 = 46
4L = 56
L = 14
and
W = L-5 = 14-5 = 9
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L*W = Area
14*9 = 126