SOLUTION: A certain number of pins are needed to fill 30 identical boxes , there being the same number of pins in each box.If 3fewer pins are put into each box there are enough pins for 32b

Algebra ->  Equations -> SOLUTION: A certain number of pins are needed to fill 30 identical boxes , there being the same number of pins in each box.If 3fewer pins are put into each box there are enough pins for 32b      Log On


   

Question 1066388: A certain number of pins are needed to fill 30 identical boxes , there being the same number of pins in each box.If 3fewer pins are put into each box there are enough pins for 32boxes. How many pins are there altogether ?
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
p= number of pins that fit per box, so that
30p= total number of pins
With p-3 pins per box,
you fill 32 boxes, so
32%28p-3%29 is also the total number of pins.
Then, our equation is
32%28p-3%29=30p .
Solving:
32%28p-3%29=30p
32p-96=30p
32p-30p=96
2p=96
p=96%2F2
p=48
So, the total number of pins is
30p=30%2A48=highlight%2814%29 .