SOLUTION: Boys received $2.95 in quarters and dimes. They received 5 more dimes than quarters. How many of each did they receive

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Question 1066206: Boys received $2.95 in quarters and dimes. They received 5 more dimes than quarters. How many of each did they receive
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
system%280.25q%2B0.1d=2.95%2Cd=q%2B5%29

system%285q%2B2d=59%2Cd=q%2B5%29

Simple substitution for d.

Answer by ikleyn(52921) About Me  (Show Source):
You can put this solution on YOUR website!
.
Answer. 7 quarters and 12 dimes.

Solution 

Take off 5 dimes from the collection, for a moment.

You will have equal number of quarters and dimes in the remaining collection, totaling 295 - 50 = 245 cents.

Group them in pairs, one quarter and one dime in each pair.

Each pair is worth 25 + 10 = 35 cents.

The number of such pairs is 245%2F35 = 7.

It implies the answer.

For coin problems and their detailed solutions see the lessons in this site:
    - Coin problems
    - More Coin problems
    - Solving coin problems without using equations
    - Kevin and Randy Muise have a jar containing coins
    - Typical coin problems from the archive
    - Solving coin problems mentally by grouping without using equations (*)
    - Santa Claus helps solving coin problem (*)

Read them attentively and become an expert in this field.
The lessons marked by (*) use this grouping method.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Coin problems".