Question 1066193: One airplane costs four times as much as a certain car. Two such planes cost $6000 more than six of the cars. Find the cost of each?
Answer by addingup(3677) (Show Source):
You can put this solution on YOUR website! p = 4c
2p = 6c+6000 substitute for p:
2(4c) = 6c+6,000
8c = 6c+6,000
2c = 6,000
c = 3,000
so the cars cost 3,000 each.
And the planes, the problem says p = 4c, thus p = 4(3,000), p = 12,000 each plane costs 12,000
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