Question 1066116: Suppose that a cyclist began a
442
mi ride across a state at the western edge of the state, at the same time that a car traveling toward it leaves the eastern end of the state. If the bicycle and car met after
6.5
hr and the car traveled
31.4
mph faster than the bicycle, find the average rate of each.
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Suppose that a cyclist began a 442 mi ride across a state,
at the western edge of the state, at the same time that a car traveling toward it leaves the eastern end of the state.
If the bicycle and car met after 6.5 hr and the car traveled 31.4 mph faster than the bicycle,
find the average rate of each.
:
When the two meet, they will have traveled a total of 442 mi
let s = speed of the bike
then
(s+31.4) = speed of the car
:
Write distance equation; dist = time * speed
:
Bike dist + Car dist = 442 mi
6.5s + 6.5(s+31.4) = 442
6.5s + 6.5s + 204.1 = 442
13s = 442 - 204.1
13s = 237.9
s = 237.9/13
s = 18.3 mph is the speed of the bike
and
18.3 + 31.4 = 49.7 mph is the speed of the car
:
:
Check this by finding the actual dist each traveled:
18.3*6.5 = 118.95 mi
49.7*6.5 = 323.05
---------------------
total mi: 442.0 mi
|
|
|
