SOLUTION: Find the​ slope-intercept form of the line perpendicular to the given​ line, passing through the given point. ​Graph the two lines. y=-2x+5 (-3,4)

Algebra ->  Linear-equations -> SOLUTION: Find the​ slope-intercept form of the line perpendicular to the given​ line, passing through the given point. ​Graph the two lines. y=-2x+5 (-3,4)      Log On


   



Question 1066097: Find the​ slope-intercept form of the line perpendicular to the given​ line, passing through the given point. ​Graph the two lines.
y=-2x+5 (-3,4)

Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
We are given
:
1) y = -2x +5 and the point (-3,4)
:
the line perpendicular to the line in 1 has a slope = negative reciprocal
:
slope = (1/2)
:
so far we have
:
y = (x/2) + b
:
now use the point in 1)
:
4 = (-3/2) + b
:
b = 4 + (3/2) = 11/2
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slope-intercept form of the line perpendicular to the line in 1) is
:
y = (x/2) +(11/2)
:
the graph below shows equation 1 in red and equation 2 in green
:

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