SOLUTION: What is the exact value of tan θ if the terminal side of angle θ, in standard position, has a length of 6 and passes through the point (-2, -y)?

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Question 1066045: What is the exact value of tan θ if the terminal side of angle θ, in standard position, has a length of 6 and passes through the point (-2, -y)?
Found 2 solutions by stanbon, josmiceli:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
What is the exact value of tan θ if the terminal side of angle θ, in standard position, has a length of 6 and passes through the point (-2, -y)?
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tan = (-y)/(-2) = y/2
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Equation:
sqrt[y^2+2^2] = 6
y^2+4 = 36
y^2 = 32
y = 5.66
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Ans: tan(t) = 5.66/2 = 2.83
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Cheers,
Stan H.
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Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Find the y-coordinate
+%28-2%29%5E2+%2B+%28-y%29%5E2+=+6%5E2+
+%28-y%29%5E2+=+36+-+4+
+y%5E2+=+32+
+y+=+4%2Asqrt%282%29++
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I'm a little confused by the +-y+. Maybe
they are saying that the y-coordinate is
negative. If so:
+tan%28+theta+%29+=+%28-4%2Asqrt%282%29+%29+%2F+%28-2%29+
+tan%28+theta+%29+=+2%2Asqrt%282%29+
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If +y+ can be either positive or
negative, then +tan%28+theta+%29+ can be
either positive or negative.