SOLUTION: SOLVING APPLICATIONS Assume that a water rocket is launched upward with initial velocity of 12 ​ft/sec. Its height​ h, in​ feet, after t​ seconds, is given

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Question 1065995: SOLVING APPLICATIONS
Assume that a water rocket is launched upward with initial velocity of 12 ​ft/sec. Its height​ h, in​ feet, after t​ seconds, is given by H=12t-16ft^2 Determine the height of the rocket one 1/2 sec after it has been launched.
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
-16t^2+12t=H(t)
H(0.5)=-4+6=2 feet.
graph%28300%2C300%2C-2%2C3%2C-2%2C8%2C-16x%5E2%2B12x%29
maximum height at -12/-32 or 3/8 second (2.25 feet)