SOLUTION: 20 spheres each of radius 3 cm have a total volume of k × pi cm^3 (as IN kpi cm^3) 1) Find k. [Already done that by equalling kpi = 20 × (4/3 × pi x 3^3) and got 720 as Ans.) 2)

Algebra ->  Volume -> SOLUTION: 20 spheres each of radius 3 cm have a total volume of k × pi cm^3 (as IN kpi cm^3) 1) Find k. [Already done that by equalling kpi = 20 × (4/3 × pi x 3^3) and got 720 as Ans.) 2)       Log On


   

Question 1065970: 20 spheres each of radius 3 cm have a total volume of k × pi cm^3 (as IN kpi cm^3) 1) Find k. [Already done that by equalling kpi = 20 × (4/3 × pi x 3^3) and got 720 as Ans.) 2) (the real problem) The spheres are inside an open cylinder with radius = 6 cm. Cylinder stands on a horizontal surface and contains enough water to cover the sphere spheres. Calculate the change in depth of water when the spheres are taken out of the cylinder. Like I found the solution to the problem but it isn't making any sense so can someone please explain it to me ? (It goes like equal 720pi(volume of 20 spheres) = pi x 6^2 ×d (where d is the change in depth of the water) ..also is there any other way to solve this problem ? (The answer is 20 btw)
Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
k = 720 and the total volume of spheres is 720 * pi cm^3
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the spheres displace their own volume in water
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note 1 ml = 1 cm^3
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pi*36*d = 720*pi
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d = 20 cm^3
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the change in depth is 20 ml
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