SOLUTION: Given: ΔKLM, KL = LM = 13in, KM = 10in. Find: The area of ΔKLM

Algebra ->  Triangles -> SOLUTION: Given: ΔKLM, KL = LM = 13in, KM = 10in. Find: The area of ΔKLM      Log On


   



Question 1065908: Given: ΔKLM, KL = LM = 13in, KM = 10in. Find: The area of ΔKLM
Answer by ikleyn(52887) About Me  (Show Source):
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Given: ΔKLM, KL = LM = 13in, KM = 10in. Find: The area of ΔKLM
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KLM is isosceles triangle.

Therefore, its median LN drawn from the vertex L is an altitude.

Therefore, the two triangles KNL an KNM are right-angled triangles.

From the triangle KNL the length of the altitude |KN| = sqrt%2813%5E2+-+%2810%2F2%29%5E2%29 = sqrt%2813%5E2-5%5E2%29 = 12.

Then the area of the triangle KLM = %281%2F2%29%2A12%2A10 = 60 squared inches.

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