SOLUTION: A snack company increases the side length of a square cracker by 2 centimeters. The new cracker has an area of 28 square centimeters larger than the old version. What was the area

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: A snack company increases the side length of a square cracker by 2 centimeters. The new cracker has an area of 28 square centimeters larger than the old version. What was the area       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 1065750: A snack company increases the side length of a square cracker by 2 centimeters. The new cracker has an area of 28 square centimeters larger than the old version. What was the area of the old cracker?
Please answer and show me how you got the answer.
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
Old cracker side length, x
New cracker side length, x+2
New cracker has a larger area than before.
The difference is 28 square centimeters.
%28x%2B2%29%5E2-x%5E2=28

Solve for x and evaluate x^2.




-
x=6
-
x%5E2=36