SOLUTION: Using substitution only find the length and width of a rectangle if perimeter is 52 m and the width is 12 more in the length
Algebra ->
Rectangles
-> SOLUTION: Using substitution only find the length and width of a rectangle if perimeter is 52 m and the width is 12 more in the length
Log On
Question 1065599: Using substitution only find the length and width of a rectangle if perimeter is 52 m and the width is 12 more in the length Answer by math_helper(2461) (Show Source):
You can put this solution on YOUR website!
Perimeter: 2l + 2w = 52m
w = l + 12 (usually the length is the longer side)
Substitute "l+12" for "w" from the bottom equation into the top one:
2l + 2(l+12) = 52
4l + 24 = 52
4l = 28 —> l=7 —> w=12+7=19
—
Ans: length is 7m, width is 19m
—
Check:
Perimeter = 2*7m + 2*19m = 14m + 38m = 52m (ok)
