SOLUTION: A train leaves Orlando at 4:00 PM. A second train leaves the same city in the same direction at 8:008 PM. The second train travels 112 mph faster than the first. If the second trai
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Question 1065563: A train leaves Orlando at 4:00 PM. A second train leaves the same city in the same direction at 8:008 PM. The second train travels 112 mph faster than the first. If the second train overtakes the first at 10:00 PM, what is the speed of each of the two trains? Answer by ikleyn(52790) (Show Source):
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A train leaves Orlando at 4:00 PM. A second train leaves the same city in the same direction at 8:00 PM.
The second train travels 112 mph faster than the first. If the second train overtakes the first at 10:00 PM,
what is the speed of each of the two trains?
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Let "v" be the speed of the first train, in mph.
Then the speed of the second train is (v+112) mph.
The equation for "t" is
6v = 2(v + 112).
6 in the left is 6 hours from 4:00 pm to 10:00 pm (till overtaking moment).
2 in the right is 2 hours from 8:00 pm to 10:00 pm (till overtaking moment).
The solution is = 56 mph.
Answer. First train speed is 56 mph. Second train speed is 56 + 112 = 168 mph.
