SOLUTION: Nico is saving money for his college education. He invests some money at 8%, and $1800 less than that amount at 6%, The investments produced a total of $270 interest in 1 year. Ho

Algebra ->  Finance -> SOLUTION: Nico is saving money for his college education. He invests some money at 8%, and $1800 less than that amount at 6%, The investments produced a total of $270 interest in 1 year. Ho      Log On


   



Question 1065392: Nico is saving money for his college education. He invests some money at 8%, and $1800 less than that amount at 6%, The investments produced a total of $270 interest in 1 year. How much did he invest at each rate?
Found 2 solutions by stanbon, josmiceli:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Nico is saving money for his college education. He invests some money at 8%, and $1800 less than that amount at 6%, The investments produced a total of $270 interest in 1 year. How much did he invest at each rate?
------
Interest Equation::
0.08x + 0.06(x-1800) = 270
--------------------------------
8x + 6x - 6*1800 = 27000
-----------------------
14x = 37800
-------
x = $2700 (amt. invested at 8%
x-1800 = $900 (amt. invested at 6%)
---------------
Cheers,
Stan H.
------------

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
For simple interest, which this is
+I+=+P%2Ar%2At+
+I+ = interest earned over +t+ years
+P+ = amount invested
+r+ = rate of interest
---------------------------
+t+=+1+ yr
Let +I%5B1%5D+ = interest earned at 8%
Let +I%5B2%5D+=+270+-+I%5B1%5D+ = interest earned at 6%
Let +P%5B1%5D+ = amount invested at 8%
+P%5B2%5D+=+P%5B1%5D+-+1800+ = amount invested at 6%
----------------------------------------------
+I%5B1%5D+=+P%5B1%5D%2A.08%2A1+
(1) +I%5B1%5D+=+.08P%5B1%5D+
and
+I%5B2%5D+=+P%5B2%5D%2A.06%2A1+
+270+-+I%5B1%5D+=+%28+P%5B1%5D+-+1800+%29%2A.06+
+270+-+I%5B1%5D+=+.06P%5B1%5D+-+108+
+.06P%5B1%5D+=+378+-+I%5B1%5D+
+P%5B1%5D+=+6300+-+%28+1%2F.06%29%2AI%5B1%5D+
(2) +P%5B1%5D+=+6300+-+%28+50%2F3+%29%2AI%5B1%5D+
Substitute (1) into (2)
(2) +P%5B1%5D+=+6300+-+%28+50%2F3+%29%2A.08%2AP%5B1%5D+
(2) +P%5B1%5D+=+6300+-+%28+50%2F3+%29%2A%28+4%2F50+%29%2AP%5B1%5D+
(2) +P%5B1%5D+=+6300+-+%28+4%2F3+%29%2AP%5B1%5D+
(2) +%28+7%2F3+%29%2AP%5B1%5D+=+6300+
(2) +P%5B1%5D+=+%283%2F7%29%2A6300+
(2) +P%5B1%5D+=+2700+
and
+P%5B2%5D+=+P%5B1%5D+-+1800+
+P%5B2%5D+=+2700+-+1800+
+P%5B2%5D+=+900+
--------------------------
He invested $2,700 @ 8%
He invested $900 @ 6%
--------------------------
check:
(1) +I%5B1%5D+=+.08P%5B1%5D+
(1) +I%5B1%5D+=+.08%2A2700+
(1) +I%5B1%5D+=+216+
and
(2) +I%5B2%5D+=+P%5B2%5D%2A.06+
(2) +I%5B2%5D+=+900%2A.06+
(2) +I%5B2%5D+=+54+
and
+I%5B1%5D+%2B+I%5B2%5D+=+216+%2B+54+
+I%5B1%5D+%2B+I%5B2%5D+=+270+
OK