SOLUTION: If P(A)=0.022, P(B)=0.068 and P(A or B)=0.248 then if follows that: A. P( A and B)=0.158 B. P(A and B)=0 C. It is not possible to have P(A)= 0.022,P(B)=0.068 and P(A or B)=0.248

Algebra ->  Probability-and-statistics -> SOLUTION: If P(A)=0.022, P(B)=0.068 and P(A or B)=0.248 then if follows that: A. P( A and B)=0.158 B. P(A and B)=0 C. It is not possible to have P(A)= 0.022,P(B)=0.068 and P(A or B)=0.248      Log On


   



Question 1065376: If P(A)=0.022, P(B)=0.068 and P(A or B)=0.248 then if follows that:
A. P( A and B)=0.158
B. P(A and B)=0
C. It is not possible to have P(A)= 0.022,P(B)=0.068 and P(A or B)=0.248.
D.There is not enough information to find P( A and B)

Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
C. It isn't possible. OR would be maximum if the two had no overlap. In that case P (A or B)= P(A)+P(B)
That sum is 0.090, and it should equal 0.248; if it were more than that, then there would be double counting of P(A and B).