SOLUTION: Solve the following inequality.
40x-84<40/x
a.) Is the point x=0 included in the solution set of the inequality?
b.)Are the other finite end points of the intervals included i
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-> SOLUTION: Solve the following inequality.
40x-84<40/x
a.) Is the point x=0 included in the solution set of the inequality?
b.)Are the other finite end points of the intervals included i
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Question 1065357: Solve the following inequality.
40x-84<40/x
a.) Is the point x=0 included in the solution set of the inequality?
b.)Are the other finite end points of the intervals included in the solution set?
c.) What is the solution set? Found 2 solutions by josgarithmetic, ikleyn:Answer by josgarithmetic(39625) (Show Source):
You can put this solution on YOUR website! Posting better solution, more complete than earlier one -
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x cannot be 0, and 0 is one of the critical x-values.
Divide both sides by 10
Concentrate on the expression on the left side
Look for the critical x-values of the numerator; the denominator has already been taken care of.
Critical x-values are and
OR after computing, .
The three critical values cut the x-axis into four intervals on which to check for solutions.
Check within each interval using the original inequality.
Pick any value within each interval.
SOLUTION: The union of and
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THIS SOLUTION POSTED EARLIER, INCOMPLETE AND WRONG:
Critical x values,
These critical x values are -2/5 and 2.5.
You will find that the solution is the x values BETWEEN BUT NOT INCLUDING -2/5 and positive 2.5. .*
*note: because of the original inequality.
You can put this solution on YOUR website! .
Solve the following inequality.
40x-84 < 40/x
a.) Is the point x=0 included in the solution set of the inequality?
b.)Are the other finite end points of the intervals included in the solution set?
c.) What is the solution set?
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Plots y = 40x - 84 (red) and y = 40/x (green)
The inequality is hold where the red line is below (lover than) the green line.
The solution set is x < and 0 < x < 2.5.
In the interval notation the solution set is (,) U (,).
The solution by "josgarithmetic" is wrong. Ignore his writing.