SOLUTION: Jane is now twice as old as Joy. In four years, she will be ten years older than Joy. Find their present ages.

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Question 1065336: Jane is now twice as old as Joy. In four years, she will be ten years older than Joy. Find their present ages.
Answer by math_helper(2461) About Me  (Show Source):
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J = Jane's age
K = Joy's age
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J = 2K (1)
J+4 = (K+4)+10 (2)
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Substitute 2K for J (from (1)) into (2):
2K+4 = K+4+10
K = 10 —> from (1): J = 2K = 20
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Ans:
Joy is 10, Jane is 20
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Check:
Joy's age in 4 years: 10+4 = 14
Jane's age in 4 years: 20+4 = 24 = 14+10 (ok, 10 more than Joy's)