SOLUTION: I need help I don't know where to start or what to do I need guidance. Triangle A,B, and C have the ratio of the sides of triangle A to triangle B is the same as ratio of the si

Algebra ->  Expressions-with-variables -> SOLUTION: I need help I don't know where to start or what to do I need guidance. Triangle A,B, and C have the ratio of the sides of triangle A to triangle B is the same as ratio of the si      Log On


   

Question 1065303: I need help I don't know where to start or what to do I need guidance.
Triangle A,B, and C have the ratio of the sides of triangle A to triangle B is the same as ratio of the sides of triangle B to triangle C.
Triangle A has a base of 5 , Triangle B shows no base # , Triangle C has 45 as base.


Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
ratio of the sides are the same, therefore:

A/B = B/C

replace A with 5 and C with 45 and you get:

5/B = B/45

cross multiply to get B^2 = 5*45

simplify to get B^2 = 225

take the square root of both sides of the equation to get B = sqrt(225).

simplify to get B = 15.

the base of A is 5.
the base of B is 15.
the Base of C is 45

the ratio of A to B is 5/15 = 1/3.

the ratio of B to C is 15/45 = 1/3.

the ratios are the same.

your solution is that the base of triangle B = 15.