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f(a+3) = 5(a+3)/4 + 2/3
= (5/4)a + (15/4) + 2/3
= (5/4)a + (45/12) + (8/12)
= (5/4)a + (53/12)
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We need to set the last line to 5 and then solve for 'a':
(5/4)a + (53/12) = 5
(5/4)a = (60/12) - (53/12)
(5/4)a = 7/12
a = (7/12)(4/5) = 28/60 = 7/15
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Now that we've solved for 'a' (=7/15), you can plug this value in for 'x' in f(x) to find the function value at 'a'.
Can you finish it from here?