SOLUTION: Using physics, it can be shown that if a ball is thrown upwards with an initial velocity
of 16 ft/s from the top of a building 64 ft high, then its height h above the ground t
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of 16 ft/s from the top of a building 64 ft high, then its height h above the ground t
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Question 1065245: Using physics, it can be shown that if a ball is thrown upwards with an initial velocity
of 16 ft/s from the top of a building 64 ft high, then its height h above the ground t
seconds later will be
h(t) = 64 + 16t − 16t2
During what time interval will the ball be at least 32 ft above the ground?
I got [0,2] but I am confused on the actual time interval. Answer by ikleyn(52847) (Show Source):
You can put this solution on YOUR website! .
Using physics, it can be shown that if a ball is thrown upwards with an initial velocity
of 16 ft/s from the top of a building 64 ft high, then its height h above the ground t
seconds later will be
h(t) = 64 + 16t − 16t2
During what time interval will the ball be at least 32 ft above the ground?
I got [0,2] but I am confused on the actual time interval.
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