SOLUTION: How much metal is needed to create a cylindrical can with a height of 5 inches and abase diameter of 3 inches?

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Question 1065225: How much metal is needed to create a cylindrical can with a height of 5 inches and abase diameter of 3 inches?

Found 2 solutions by math_helper, Alan3354:
Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!
The amount of metal needed would be the volume needed. The formula for the volume of a cylinder is:
+V=pi%2Ar%5E2h+
Where r is the radius of the base
and h is the height of the cylinder

You can think of the volume of a cylinder as the area of the base (pi*r^2) times the height (h). Its also always a good idea to look at units. in^2 (base area) x in will give a volume with units of in^3 which is correct.

The problem statement gives you the height, and it gives the diameter of the base, just divide the base by 2 to get the radius, then plug in both numbers into the formula.

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
How much metal is needed to create a cylindrical can with a height of 5 inches and abase diameter of 3 inches?
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Each end of the can has an area of pi*r^2 = 2.25pi sq inches
The lateral area is pi*d*h = 15pi sq inches