SOLUTION: A train leaves Chicago headed to Cleveland at the same time the second train leaves from Cleveland to Chicago, 340 Miles away. if they met four hours into the trip and the second t

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Question 1065193: A train leaves Chicago headed to Cleveland at the same time the second train leaves from Cleveland to Chicago, 340 Miles away. if they met four hours into the trip and the second train travels 15 mi/hr. slower than the first, how fast is each train traveling
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
I like to solve this type problem by saying
that one train is standing still and the other
one is travelling at the sum of their speeds
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Let +s+ = the speed of the faster train
+s+-+15+ = the speed of the slower train
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Add their speeds
+340+=+%28+s+%2B+s++-+15+%29%2A4+
+340+=+%28+2s++-+15+%29%2A4+
+340+=+8s+-+60+
+8s+=+400+
+s+=+50+
and
+s+-+15+=+35+
Their speeds are 50 mi/hr and 35 mi/hr
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check:
+d%5B1%5D+=+50%2A4+
+d%5B1%5D+=+200+
and
+d%5B2%5D+=+35%2A4+
+d%5B2%5D+=+140+
and
+d%5B1%5D+%2B+d%5B2%5D+=+340+
as it should be