Question 1065096: Find three consecutive even integers such that four times the third integer is four more than three times the first integer plus two times the second integer.
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Find three consecutive even integers such that four times the third integer is four more than three times the first integer plus two times the second integer.
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Three consecutive even integers: n, (n+2), (n+4)
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write an equation for exactly what it says
4(n+4) = 3n + 4 + 2(n+2)
Distribute, combine like terms
4n + 16 = 3n + 4 + 2n + 4
4n + 16 = 5n + 8
16 - 8 = 5n - 4n
8 = n
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8, 10, 12 are the integers
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Check solution in the statement
" four times the third integer is four more than three times the first integer plus two times the second integer."
4(12) = 3(8) + 4 + 2(10)
48 = 24 + 4 + 20
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