SOLUTION: The product of two consecutive odd number is 6723. What is greater number?

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Question 1064926: The product of two consecutive odd number is 6723. What is greater number?
Found 4 solutions by josmiceli, josgarithmetic, MathTherapy, Alan3354:
Answer by josmiceli(19441) About Me  (Show Source):
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Let the consecutive odd numbers be
+n+ and +n+%2B+2+
----------------------
+n%2A%28+n+%2B+2+%29+=+6723+
+n%5E2+%2B+2n+=+6723+
Complete the square
+n%5E2+%2B+2n+%2B+%282%2F2%29%5E2+=+6723+%2B+%282%2F2%29%5E2+
+n%5E2+%2B+2n+%2B+1++=+6724+
+%28+n+%2B+1+%29%5E2+=+82%5E2+
+n+%2B+1+=+82+
+n+=+81+
and
+n+%2B+2+=+83+
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The larger number is 83
------------------------
check:
+81%2A83+=+6723+
+6723+=+6723+
OK

Answer by josgarithmetic(39630) About Me  (Show Source):
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-81 and -83
OR
81 and 83

Two consecutive odd numbers for any integer n:
2n+1 and 2n+3.
%282n%2B1%29%282n%2B3%29=6723
4n%5E2%2B8n%2B3=6723
n%5E2%2B2n-6720
Factorize or use solution for quadratic equation,
n=-42 or n=40.
Evaluate 2n+1 and 2n+3.

Answer by MathTherapy(10557) About Me  (Show Source):
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The product of two consecutive odd number is 6723. What is greater number?
Take the square root of 6,723, which is matrix%281%2C1%2C+%22+%22+%2B-+%2281.%2B%2B%2B%2B%22%29
Therefore, integers are: matrix%281%2C7%2C+81%2C+and%2C+83%2C+or%2C+-+81%2Cand%2C+-+83%29. You should be able to tell the LARGER of each pair.

Answer by Alan3354(69443) About Me  (Show Source):
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If you want to do it the hard way, use n-1 and n+1
Not n and n+2
=====================
(n-1)*(n+1) = n^2 - 1 = 6723
n+=+sqrt%286724%29
n = ±68
etc