SOLUTION: What is the equation of a line that is perpendicular to −x+3y=9 and passes through the point (−3,2)?

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Question 1064810: What is the equation of a line that is perpendicular to −x+3y=9 and passes through the point (−3,2)?
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
rewrite as 3y=x+9 and divide by 3 to get y=(1/3)x+3.
The slope is (1/3), so the perpendicular line has a negative reciprocal, meaning the product of both slope is -1. The slope of the perpendicular line is -3.
point slope formula for (-3,2)
y-y1=m(x-x1), m the slope, (x1,y1) the point
y-2=-3(x-(-3))
y-2=-3x-9
y=-3x-7
graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C%28x%2F3%29%2B3%2C-3x-7%29