SOLUTION: Lucy can paint a wall in 5 hours and working with Pedro the two of them can paint the fence in 2 hours. Exactly how long would it have taken Pedro to paint the fence alone?

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Question 1064602: Lucy can paint a wall in 5 hours and working with Pedro the two of them can paint the fence in 2 hours. Exactly how long would it have taken Pedro to paint the fence alone?
Answer by ikleyn(52783) About Me  (Show Source):
You can put this solution on YOUR website!
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Working together, they paint 1%2F2 of the area in one hour.

Working alone, Lucy paints 1%2F5 of the area in one hour.

Hence, Pedro paints 1%2F2+-+1%2F5 = 5%2F10+-+2%2F10 = 3%2F10 of the area per hour.

It means that Pedro takes 10%2F3 hours to paint the room working alone.

10%2F3 hours = 3 1%2F3 hours = 3 hours and 20 minutes.


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For a wide variety of similar solved joint-work problems with detailed explanations see the lessons
    - Using Fractions to solve word problems on joint work,
    - Solving more complicated word problems on joint work,
    - Selected joint-work word problems from the archive
in this site.

Read them and get be trained in solving joint-work problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook under the topic "Rate of work and joint work problems" of the section "Word problems".