SOLUTION: Evaluate sin2x + cos2x when tanx = -2

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Question 1064582: Evaluate sin2x + cos2x when tanx = -2
Answer by ikleyn(52877) About Me  (Show Source):
You can put this solution on YOUR website!
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Evaluate sin2x + cos2x when tanx = -2
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Use the formulas of half argument written for 2x and x:


sin(2x) = %282%2Atan%28x%29%29%2F%281+%2B+tan%5E2%28x%29%29,  cos(2x) = %281-tan%5E2%28x%29%29%2F%281+%2B+tan%5E2%28x%29%29.


For these formulas see, for example, the lesson
    - FORMULAS FOR TRIGONOMETRIC FUNCTIONS 
in this site.


By applying them, you will get

sin(2x) + cos(2x) = %282%2Atan%28x%29%29%2F%281+%2B+tan%5E2%28x%29%29 + %281-tan%5E2%28x%29%29%2F%281+%2B+tan%5E2%28x%29%29 = %282%2A%28-2%29%29%2F5+%2B+%28-3%29%2F5 = -7%2F5.


Answer.  -7%2F5.