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| Question 106454:  Janet invested $31,000, part at 10% and part at 1%.  If the total interest at the end of the year is $1,390, how much did she invest at 10%?
 Answer by checkley75(3666)
      (Show Source): 
You can put this solution on YOUR website! .10X+.01(31,000-X)=1.390 .10X+310-.01X=1,390
 .09X=1,390-310
 .09X=1,080
 X=1,080/.09
 X=12,000 INVESTED @ 10%.
 PROOF
 .10*12,000+.01*19,000=1,390
 1200+190=1,390
 1,390=1,390
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