Question 1064537: suppose you work in a lab. You need a 200ml of a 35% acid solution for a certain test, but your supplier only ships a 25% solution and a 50% solution. Rather than pay ther hefty surcharge to have the supplier make a 35% solution, you decide to mix 25% acid solution with 50% acid solution, to make your own 35% acid solution. How many milliliters of each solution should you use to form 200ml of a 35% acid solution?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! ): suppose you work in a lab. You need a 200ml of a 35% acid solution for a certain test, but your supplier only ships a 25% solution and a 50% solution. Rather than pay ther hefty surcharge to have the supplier make a 35% solution, you decide to mix 25% acid solution with 50% acid solution, to make your own 35% acid solution. How many milliliters of each solution should you use to form 200ml of a 35% acid solution?
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Equation:
acid + acid = acid
0.25x + 0.50(200-x) = 0.35*200
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25x + 50*200 - 50x = 35*200
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-25x = -10*200
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x = 10*8 = 80 ml (amt. of 25% solution needed)
200-x = 120 ml (amt. of 50% solution needed)
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Cheers,
Stan H.
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