SOLUTION: A) express cos3x in terms of cosx. I have already gotten the answer for this to be 4coscubex-3cosx
B) hence, solve, for 0<x<2(3.14),the equation cos3x+2cos2x+4cosx+2=0.
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Trigonometry-basics
-> SOLUTION: A) express cos3x in terms of cosx. I have already gotten the answer for this to be 4coscubex-3cosx
B) hence, solve, for 0<x<2(3.14),the equation cos3x+2cos2x+4cosx+2=0.
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Question 1064487: A) express cos3x in terms of cosx. I have already gotten the answer for this to be 4coscubex-3cosx
B) hence, solve, for 0 Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! A) express cos3x in terms of cosx. I have already gotten the answer for this to be 4coscubex-3cosx
cos(3x) = 4cos^3(x) - 3cos(x)
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Use parentheses and ^ for exponents.
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B) hence, solve, for 0 < x < 2pi, the equation cos3x+2cos2x+4cosx+2=0.
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Is it cos^3(x) ?
or cos(3x) ?
