SOLUTION: The rectangle has length that is 5 feet less than twice its width and it has an area of 85.9 square feet. What are the dimensions to the nearest tenth of a foot?

Algebra ->  Rectangles -> SOLUTION: The rectangle has length that is 5 feet less than twice its width and it has an area of 85.9 square feet. What are the dimensions to the nearest tenth of a foot?       Log On


   

Question 1064367: The rectangle has length that is 5 feet less than twice its width and it has an area of 85.9 square feet. What are the dimensions to the nearest tenth of a foot?

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
system%28L=-5%2B2w%2CwL=85.9%29

w%282w-5%29=85.9

2w%5E2-5w-85.9=0

w=%285%2B-+sqrt%2825%2B4%2A2%2A85.9%29%29%2F%282%2A2%29

w=%285%2B-+sqrt%2896.2%29%29%2F4

highlight%28w=%285%2Bsqrt%2896.2%29%29%2F4%29
Simplify further and use it for finding L.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

The rectangle has length that is 5 feet less than twice its width and it has an area of 85.9 square feet. What are the dimensions to the nearest tenth of a foot?