n = first integer
n+1 = second integer
n+2 = third integer
n+3 = fourth integer
The sum of four consecutive positive integers is 'X"
n+(n+1)+(n+2)+(n+3) = X
n+n+1+n+2+n+3 = X
4n+6 = X
4n = X-6
n =
n+1 = second integer =
n+2 = third integer =
What is the sum of the second and third integers?
Edwin