SOLUTION: A chandelier is suspended from a horizontal beam by two support chains. One of the chains is 3.6 m long and from an angle of 62 dregres with the beam. The second chain is 4.8 m lon
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-> SOLUTION: A chandelier is suspended from a horizontal beam by two support chains. One of the chains is 3.6 m long and from an angle of 62 dregres with the beam. The second chain is 4.8 m lon
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Question 1064328: A chandelier is suspended from a horizontal beam by two support chains. One of the chains is 3.6 m long and from an angle of 62 dregres with the beam. The second chain is 4.8 m long what's the angle does the second chain make with the beam Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! It is worth drawing this.
The chandelier hangs down vertically, and the sine of the angle 62 equals the opposite side (the chandelier's length) divided by the hypotenuse, which is the length of the chain.
sin 62=opposite/3.6
opposite side=3.6 sin 62=3.18 m
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The other chain is 4.8 m (hypotenuse) and it also has an opposite side of 3.18 m
The sin of that angle is 3.18/4.8=0.6625
Take the arc sin of that and get 41.49 degrees.
